Fat Freddy wrote:
You have most certainly counted correctly as I have not allowed for the missing teeth.
I think I didn't.
. My apologies. 2X 2 missing teeth. So 36 teeth. Which is a nicer number 10* each
I'd reitterate what FF says here - you need to use 36 as the number of teeth per engine revolution for this example, not 34 or 32. Fundamental to what FF is saying is that when you make a maths channel calculation for speed from a tooth frequency, you must use the tooth count as if there are no missing teeth, e.g. in this case add the 4 missing teeth to the counted 32 for a revolution. Then just reject the data at the missing teeth (drop-outs) in the speed calculation.
Am I missing something in the start of the thread here - all four cylinders DO look as if they are contributing equally, not the statement that No.1 is NOT contributing equally?